2 Answers

Yohann · Answer 1 · 2020-04-28T02:45:28+0000

Hello!

The answer is:

To solve for "x" , we just need to isolate it from the equation.

So, we are given the equation:

n(17+x)=34z-r

Then, isolating we have:

$n(17+x)=34z-r\\\\17+x=(34z-r)/(n)\\\\x=(34z-r)/(n)-17$

Hence, the answer is:

x=(34z-r)/(n)-17

Have a nice day!

Cheshirekow · Answer 2 · 2020-04-30T07:14:32+0000

Answer:

x=(34z-r)/(n)-17

Explanation:

Given

n(17+x)=34z-r

We have to isolate x on one side of the equation

Dividing both sides by n

(n(17+x))/(n) =(34z)/(n)-(r)/(n)

Taking LCM on left side

17+x = (34z-r)/(n)

Subtracting 17 from both sides

17+x-17 = (34z-r)/(n)-17

So, the value of x will be:

x=(34z-r)/(n)-17 ..