Question

When a 1.50V battery is shorted by a copper wire whose resistance can be ignored, the current through the copper wire is 2.75 A. What is the internal resistance of the battery?

Answer 1

Internal resistance = 0.545 ohm

Step-by-step explanation:

As per ohm's law we know that

`V = iR`

here we know that

i = electric current = 2.75 A

V = potential difference = 1.50 Volts

now from above equation we have

`1.50 = 2.75 ( R)`

now we have

`R = (1.50)/(2.75)`

`R = 0.545 ohm`