Question

A force of 4400 N is exerted on a piston that has an area of 0.020 m.

What force is exerted on a second piston that has an area of 0.040 m-?
A. 8800
B.220,000
C.88
D.2200

Answer 1

use pascal's law..to solve the question

Answer 2

Use Pascal's Law.

F1/A1 = F2/A2

F1 = 4400N

A1 = 0.020m^2

F2 = X

A2 = 0.040m^2

4400/0.020 = X/0.040

Cross multiply:

(4400 * 0.040) = 0.020X

176 = 0.020x

Divide both sides by 0.020

X = 176 / 0.020

X = 8800

The force is 8800 N