Question

Sustained current as small as 2.50×10^–6 A passing through the human heart can be fatal. Suppose a patient is undergoing open-heart surgery, and the patient’s heart has a constant resistance of 273 Ω. What is the minimum voltage across the heart that could pose a danger to the patient?

Answer 1

Minimum voltage, V = 0.682 mV

Step-by-step explanation:

It is given that,

Current passing through the human heart,
`I=2.5* 10^(-6)\ A`

A patient is undergoing open-heart surgery, and the patient’s heart has a constant resistance, R = 273 ohms

We have to find the minimum voltage across the heart that could pose a danger to the patient. It can be calculated using Ohm's law as :

V = IR

`V=2.5* 10^(-6)\ A* 273\ \Omega`

V = 0.0006825 volts

or

V = 0.682 mV

Hence, the minimum voltage across the heart that could pose a danger to the patient is 0.682 mV