Question

A child pulls a wagon at a constant velocity along a level sidewalk. The child does this by applying a 22 newton force to the wagon handle, which is inclined at 35° to the sidewalk as shown below. What is the magnitude of the fore of friction on the wagon?

Answer 1

The answer is 18 N.

Step-by-step explanation:

A force can be divided into components x and y components. The component along the x-axis is called the horizontal component and along the y-axis is called the vertical component. In this case, as the force is in a horizontal direction and is also known as x-component of force. The x- component of force is

Fx = Fcosθ

Fx = 22(cos 35°)

Fx = 22 x 0.819

Fx = 18 N

Child's horizontal pull forces are equal to that of frictional resistance force on the wagon.