Question

A piece of plastic has a net charge of +9.9 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60 x 10^-19 C). (Divide your answer by 10^13, and give the result to the nearest 0.01

Answer 1

The number of protons 6.19 more than electron.

Step-by-step explanation:

Given that,

Charge
`Q=+9.9*10^(-6)\ C`

We know that,

formula of charge

`Q = nc`

Where,

Q = total charge

n = number of protons

e = charge of electron

Put the value into the formula

`n = (Q)/(e)`

`n=(9.9*10^(-6))/(1.6*10^(-19))`

`n=6.1875*10^(13)\ C`

According to statement of question

Divide the answer by
`10^(13)`

`n=(6.1875*10^(13))/(10^(13))`

`n=6.19\ C`

Hence, The number of protons 6.19 more than electron.