Answer:
So there are 35 quarters and 21 nickels.
Explanation:
So I guess that is all we have is quarters and nickels.
Quarters are worth .25
Nickels are worth .05
Let x represent the number of quarters
Let y represent the number of nickels
x+y=56
.25x+.05y=9.8
We are going to solve this system.
I'm going to use substitution. I will solve the first equation for y and then plug that into the second equation.
y=56-x
.25x+.05(56-x)=9.8
.25x+2.8-.05x=9.8
.20x+2.8=9.8
.2x = 7
x=7/(.2) or 7*5=35
y=56-x
y=56-35=21
So there are 35 quarters and 21 nickels.