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Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag

User AUSteve
by
6.9k points

2 Answers

6 votes

Answer:


3.966* 10^(24) pure silver atoms are produced.

Step-by-step explanation:


1 mol = N_A=6.022* 10^(23) mol^(-1)

Atoms of copper =
19.83* 10^(23)

Moles of copper =
(19.83* 10^(23) )/(N_A)


=(19.83* 10^(23) )/(6.022* 10^(23) mol^(-1))=3.293 mol


Cu + 2AgNO_3\rightarrow Cu(NO_3)_2 + 2Ag

According to reaction, 1 mol of copper atoms gives 2 moles of silver atoms.

Then 3.293 moles of moles of copper will give:


(2)/(1)* 3.293 mol=6.586 mol

Number of silver atoms in 6.586 moles of silver:

=
6.586 mol* 6.022* 10^(23) mol^(-1)=3.966* 10^(24) atoms

User Talha Malik
by
7.7k points
0 votes

Answer:


\boxed{3.966 * 10^(24)\text{ atoms of Ag}}

Step-by-step explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu


\text{Atoms of Ag} = 19.83 * 10^(23)\text{atoms Cu} * \frac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 * 10^(24)\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 * 10^(24)}\textbf{ atoms of Ag}}

User Nilo De Roock
by
7.6k points