28.5k views
5 votes
A sequence is defined by the following:

A1 = 6 and an = -1.2n-1
What is the 4th term?
-12.4416
-10.368
10.368
12.4416

A sequence is defined by the following: A1 = 6 and an = -1.2n-1 What is the 4th term-example-1

2 Answers

4 votes

Answer:

Explanation:

a1 = 6

a2 = -1.2*a_(n-1)

a2 = -1.2*a_1

a2 = -1.2 * 6

a2 = -7.2

a3 = -1.2*a_(n-1)

a3 = -1.2*a_2

a3 = -1.2 * - 7.2

a3 = 8.64

a4 = -1.2 * a_3

a4 = -1.2 * 8.64

a4 = -10.368

User Nobism
by
8.8k points
5 votes

Answer: The correct option is (B) -10.368.

Step-by-step explanation: Given that a sequence is defined b the following :


a_1=6,~~~a_n=-1.2a_(n-1).

We are to find the 4-th term.

To find the fourth term, we need to start from finding the first term.

If n = 2, then the second term is given by


a_2=-1.2* a_1=-1.2* 6=-7.2.

If n = 3, then the third term is given by


a_3=-1.2* a_2=-1.2* (-7.2)=8.64.

If n = 4, then the fourth term is given by


a_4=-1.2* a_3=-1.2* 8.64=-10.368.

Thus, the fourth term of the given sequence is -10.368.

Option (B) is CORRECT.

User Myxtic
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories