Question

What is the slope of a line perpendicular to the line represented by the equation y=-2/5x+4/5

Answer 1

`\large\boxed{m=(5)/(2)}`

Explanation:

`\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-(1)/(m_1)\\\\l\ \parallel\ k\iff m_1=m_2\\\\===================================\\\\\text{We have the equation of a line:}\ y=-(2)/(5)x+(4)/(5)\to m_1=-(2)/(5).\\\\m_2=-(1)/(m_1)\to m_2=-(1)/(-(2)/(5))=(5)/(2)`