Answer:
Explanation:
X²=12x-40
X²-12x+40=0
a=1 and b= -12 and c = 40
delta = b² - 4ac
delta = (-12)² - 4(1)(40) = 144 - 160 = - 16 = (4i)² ....i² = -1
x1= (12-4i)/2 =6-2i
x1= (12+4i)/2 =6+2i
x^2 = 12 x-40
x² - 12x + 40 = 0
a = 1; b = -12; c = 40
4ac - b² = 4*1*40 - (-12)² = 160 - 144 = 16
x = -b ± √4ac-b² i / 2a
= -(-12) ± √ 16 i
2 * 1
= (12 ± 4 i )/ 2
= 2( 6 ± 2i)
2
= 6 ± 2i
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