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If the variance of the ages of the people who attended a rock concert is 38, what is the standard deviation of the ages? Round your answer to two decimal places

User Btilly
by
7.6k points

2 Answers

4 votes

Answer:


\sigma=6.16

Explanation:

By definition, the variance V of a population is defined as:


V = \sigma^2

Where
\sigma is the standard deviation

We know that
V = 38, then we can solve the equation for the standard deviation
\sigma


38 = \sigma^2


\sigma^2=38


\sigma=√(38)


\sigma=6.16

Finally the standard deviation is:
\sigma=6.16

User Jamie Schembri
by
7.9k points
2 votes

Answer:

The standard deviation of the age is 6.16

Explanation:

* Lets talk about the variance and the standard deviation

- The variance is the measure of how much values in a set of data are

likely to differ from the mean value of the same data

- The steps to find the variance are:

1- Find the mean of the data

2- Subtract the mean from each value and square the answer

3- Add all of these squared answer and divide the sum by the number

of the values

- The answer of the step 3 is The variance (σ²)

- The standard deviation (σ) is the square root of the variance

* Now lets solve the problem

∵ The variance of the ages of the people who attended a rock

concert is 38

∴ σ² = 38

∵ The standard deviation is the square root of the variance

∴ σ = √38 = 6.16

* The standard deviation of the age is 6.16

User David Oliver
by
7.4k points