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If the variance of the ages of the people who attended a rock concert is 38, what is the standard deviation of the ages? Round your answer to two decimal places

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Answer:


\sigma=6.16

Explanation:

By definition, the variance V of a population is defined as:


V = \sigma^2

Where
\sigma is the standard deviation

We know that
V = 38, then we can solve the equation for the standard deviation
\sigma


38 = \sigma^2


\sigma^2=38


\sigma=√(38)


\sigma=6.16

Finally the standard deviation is:
\sigma=6.16

User Njol
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