Question

For f(x)=3x+1 and get g(x) =x2-6, find (f-g)(x)

Answer 1

(f - g)(x) = (3x + 1) - (x2 - 6) = 3x + 1 - x2 + 6 = -x2 + 3x + 7

i hope this helps.

Answer 2

For this case we have the following functions:

`f (x) = 3x + 1\\g (x) = x ^ 2-6`

We must find
`(f-g) (x).`

By definition we have to:

`(f-g) (x) = f (x) -g (x)`

So:

`(f-g) (x) = 3x + 1- (x ^ 2-6)\\(f-g) (x) = 3x + 1-x ^ 2 + 6\\(f-g) (x) = - x ^ 2 + 3x + 6 + 1\\(f-g) (x) = - x ^ 2 + 3x + 7`

Answer:

`(f-g) (x) = - x ^ 2 + 3x + 7`