226k views
5 votes
What is the equation of the line that passes through the points (2, –1) and (6, 1)? A.y=1/2x -2 B.y=2x-5 C.y=-1/2x-1 D. y=-2x-3

User Fieldju
by
8.1k points

1 Answer

2 votes

Answer:

option A.

y = (1/2)x - 2

Explanation:

It is given that, line that passes through the points (2, –1) and (6, 1)

Slope m = (y₂ - y₁)/(x₂ - x₁)

= (1 - -1)/(6 - 2)

= (1 + 1)/4 = 2/4

= 1/2

To find the equation of the line

Equation of a line passing through the points (x₁, y₁) and slope m is given by,

(y - y₁)/(x - x) = m

Here (x₁, y₁) = (2, -1) and m = 1/2

(y - -1)/(x - 2) = 1/2

(y + 1) = (x - 2)/2

y = -1 + x/2 - 2/2

= -1 + x/2 - 1

= x/2 - 2

The equation of the line is,

y = (1/2)x - 2

The correct answer is option A.

y = (1/2)x - 2

User Mansu
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories