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What is the equation of the line that passes through the points (2, –1) and (6, 1)? A.y=1/2x -2 B.y=2x-5 C.y=-1/2x-1 D. y=-2x-3

User Fieldju
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1 Answer

2 votes

Answer:

option A.

y = (1/2)x - 2

Explanation:

It is given that, line that passes through the points (2, –1) and (6, 1)

Slope m = (y₂ - y₁)/(x₂ - x₁)

= (1 - -1)/(6 - 2)

= (1 + 1)/4 = 2/4

= 1/2

To find the equation of the line

Equation of a line passing through the points (x₁, y₁) and slope m is given by,

(y - y₁)/(x - x) = m

Here (x₁, y₁) = (2, -1) and m = 1/2

(y - -1)/(x - 2) = 1/2

(y + 1) = (x - 2)/2

y = -1 + x/2 - 2/2

= -1 + x/2 - 1

= x/2 - 2

The equation of the line is,

y = (1/2)x - 2

The correct answer is option A.

y = (1/2)x - 2

User Mansu
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