First you must distribute the numbers outside the parentheses to the numbers inside the parentheses
Let's start with the first one:
9(x-2) + 3(5-2x) = 2
9(x - 2)
9*x + 9*-2
9x + (-18)
9x - 18
so...
9x - 18 + 3(5-2x) = 2
Now on to the second set of parentheses:
9x - 18 + 3(5-2x) = 2
3(5 - 2x)
3*5 + 3*-2x
15 + (-6x)
15 - 6x
so...
9x - 18 + 15 - 6x = 2
Now you must combine like terms. This means the numbers with the same variables must be combined...
First set of like terms:
9x - 18 + 15 - 6x = 2
9x + (-6x)
3x
so...
3x - 18 + 15 = 2
Second set of like terms:
3x - 18 + 15 = 2
-18 + 15
-3
so...
3x - 3 = 2
Now bring -3 to the right side by adding 3 to both sides (what you do on one side you must do to the other). Since -3 is being negative on the left side, addition (the opposite of negative/subtraction) will cancel it out (make it zero) from the left side and bring it over to the right side.
3x + (- 3 + 3) = 2 + 3
3x + 0 =5
3x = 5
Next divide 3 to both sides to finish isolating x. Since 3 is being multiplied by x, division (the opposite of multiplication) will cancel 3 out (in this case it will make 3 one) from the left side and bring it over to the right side.
3x/3 = 5/3
x =
Hope this helped!
~Just a girl in love with Shawn Mendes