Answer: Option B
Explanation:
By definition, only those functions that are one to one have an inverse function.
A function is one by one if there are not two different input values,
and
, that have the same output value y
Note that the function
is not a one-to-one function
When x=2
![f(x)= (|2+3|)/(5)=1\ ,\ \ y=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lny701aazj1y6pable7ieu4vsxh12evbo1.png)
When x=8
![f(x)= (|-8+3|)/(5)=1\ \ ,\ y=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a0li2gxu5y2cwp6qotirgejc1wx9pyzo0t.png)
Note that the function
is not a one-to-one function
When x=1
![f(x)= ((1)^4)/(7)+27\ ,\ \ y=(190)/(7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n92llm6i3ajaisduhqufn268fa754ctfcg.png)
When x=-1
![f(x)= ((-1)^4)/(7)+27\ ,\ \ y=(190)/(7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ztl8tqu7i2ab8ch2n5pu14k1788acwjye4.png)
Note that the function
is not a one-to-one function
When x=1
![f(x)= (1)/((1)^2)\ ,\ \ y=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iik2tc5zj7fmbqyzkoejmddejpxcjoug8u.png)
When x=-1
![f(x)= (1)/((-1)^2)\ ,\ \ y=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6112jtdw8r604p38tqxbnf9yjzpwdknv18.png)
Then the answer is the option B.
You can verify that The function
is a one-to-one function and therefore its inverse is a function