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write the balanced net ionic equation for the reaction of aqueous sodium sulfide with aqueous lead(II) nitrate

User Allo
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Final answer:

The balanced net ionic equation is Na2S(aq) + Pb(NO3)2(aq) → PbS(s) + 2NaNO3(aq).

Step-by-step explanation:

The balanced net ionic equation for the reaction of aqueous sodium sulfide with aqueous lead(II) nitrate is:

Na2S(aq) + Pb(NO3)2(aq) → PbS(s) + 2NaNO3(aq)

In this reaction, sodium sulfide reacts with lead(II) nitrate to form a solid precipitate of lead sulfide and a solution of sodium nitrate. The balanced net ionic equation represents only the species that undergo a chemical change, while the spectator ions are left out.

User Thomas Winsnes
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