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F(n + 1) = f(n) – 8. If f(1) = 100, what is f(6)?

User Poorva
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f(n+1)=f(n)-8\\f(1)=100\\\\f(2)=100-8=92\\f(3)=92-8=84\\f(4)=84-8=76\\f(5)=76-8=68\\f(6)=68-8=60

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