Question

If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb's constant is k = 9.0x 10^9 N-m^2/C^2? 9.5 m 9.0 mm 9.5 cm 0.9 m .

Answer 1

The distance between the charges is 9.5 cm

(c) is correct option

Step-by-step explanation:

Given that,

Charge
`q= 10^(-6)\ C`

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

`F = (kq_(1)q_(2))/(r^2)`

Where, q = charge

r = distance

F = force

Put the value into the formula

`1=(9.0*10^(9)*(-10^(-6))^2)/(r^2)`

`r=\sqrt{9*10^(9)*(-10^(-6))^2}`

`r=0.095\ m`

`r= 9.5\ cm`

Hence, The distance between the charges is 9.5 cm