Question

For an aqueous solution of sodium chloride (NaCl), determine the molarity of 3.95 L of a solution that contains 143 g of sodium chloride.

-Determine the volume of this solution that would contain 3.93 moles of sodium chloride.
-Determine the number of moles of sodium chloride in 20.55 L of this solution.

Answer 1

1.) 0.619 M

2.) 6.34 L

3.) 12.7 moles

Step-by-step explanation:

Part 1: To find the molarity, you first need to convert grams to moles using the molar mass.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

143 grams NaCl 1 mole
------------------------- x ------------------------ = 2.45 moles NaCl
58.443 grams

Molarity = moles / volume (L)

Molarity = 2.45 moles / 3.95 L

Molarity = 0.619

Part 2: To find the volume, you need to use the given moles and the previously calculated molarity.

Molarity = moles / volume (L)

0.619 M = 3.93 moles / volume

(0.619 M) x volume = 3.93 moles

volume = 6.34

Part 3: To find the moles, you need to use the given volume and the previously calculated molarity.

Molarity = moles / volume (L)

0.619 M = moles / 20.55 L

12.7 = moles