Question

An automobile of mass 2000 kg moving at 30 m/s is braked suddenly with a constant braking force of 10000 N. How far does the car travel before stopping?

Answer 1

The car traveled the distance before stopping is 90 m.

Step-by-step explanation:

Given that,

Mass of automobile = 2000 kg

speed = 30 m/s

Braking force = 10000 N

For, The acceleration is

Using newton's formula

`F = ma`

Where, f = force

m= mass

a = acceleration

Put the value of F and m into the formula

`-10000 =2000* a`

Negative sing shows the braking force.

It shows the direction of force is opposite of the motion.

`a = -(10000)/(2000)`

`a=-5\ m/s^2`

For the distance,

Using third equation of motion

`v^2-u^2=2as`

Where, v= final velocity

u = initial velocity

a = acceleration

s = stopping distance of car

Put the value in the equation

`0-30^2=2*(-5)* s`

`s = 90\ m`

Hence, The car traveled the distance before stopping is 90 m.