Question

Given f(x) = 17-X^2what is the average rate of change in f(x) over the interval [1, 5]?

Answer 1

-6

Explanation:

Answer 2

-6

Explanation:

The formula for finding the rate of change is:

`Rate\ of\ change=(f(b)-f(a))/(b-a)`

The interval is [1,5]

So, a = 1 and b=5

`f(1) = 17 - (1)^2\\ =17-1\\=16\\f(5) = 17-(5)^2\\=17-25\\=-8`

Putting in the values

`Rate\ of\ change = (f(5)-f(1))/(5-1) \\=(-8-16)/(5-1)\\= (-24)/(4)\\ =-6`

The average rate of change is -6 ..