Question

What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y − 1?

P = 2x + 2y + 18

P = 2x + 2y + 14

P = x + y − 9

P = x + y + 7

Answer 1

P = 2x + 2y + 14

Explanation:

Answer 2

P = 2x + 2y + 14

Explanation:

Length (L) = x + 8 units

Width (W) = y - 1 units

Perimeter (P) = 2L + 2W

P = 2(x + 8) + 2(y - 1)

P = 2x + 16 + 2y - 2

P = 2x + 2y + 16 - 2

P = 2x +2y + 14