Question

If 8=x+y and y>0, then x is

Answer 1

x<8

Explanation:

We have one equation and one inequation:

8=x+y [1]

y>0 [2]

Solving [1] for 'y' we have:

8=x+y → y = 8-x

If y>0, then 'x' must be less than 0. Given that if 'x' is equal or greater than 8, 'y' will take negative values.

Then: x<8