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In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then

do the calculation
How many ways are there to pick a starting five from a basketball team of twelve members?
a. Permutation; Ps - 2520
b. Combination; 1C, - 792
c. Combination: 2Cs - 2520
d. Permutation; Ps - 95040

2 Answers

5 votes

Answer is D

Explanation:

User Anubhav Pandey
by
5.1k points
3 votes

Answer:

There are 95040 ways to chose the starting five players

The answer is d ⇒ Permutation; Ps - 95040

Explanation:

* Lets explain the difference between permutations and combinations

- Both permutations and combinations are collections of objects

- Permutations are for lists (order matters)

- Combinations are for groups (order doesn't matter)

- A permutation is an ordered combination.

- Permutation is nPr, where n is the total number and r is the number

of choices

# Example: chose the first three students from the group of 10 students

n = 10 and r = 3,then 10P3 is 720

- Combinations is nCr, where n is the total number and r is the number

of the choices

# Example: chose a group of three students from the group of 10 students

n = 10 and r = 3,then 10C3 is 120

* Lets solve the problem

- We want to pick starting five players from a basketball team of

twelve players

∵ We will pick the starting five

∴ The order is important

∴ We will use the permutations

∵ The total number of the players is 12

∵ The number of choices is 5

∴ n = 12 and r = 5

∵ The number of ways is nPr

∴ 12P5 = 95040

∴ There are 95040 ways to chose the starting five players

User Pradeep Bhadani
by
5.5k points