Answer:
The equation which is correct for the given function is:
D.

Explanation:
By looking at the graph we observe that the graph of the function passes through the point (-4,0) , (-2,0) , (-3,-2)
A)

when x= -3 we have:

Hence, option: A is incorrect.
B)

when x= -2 we have:

Hence, option: B is incorrect.
C)

when x= -2 we have:


Hence, option: C is incorrect.
D)

We see that the graph of this equation matches the given graph of the function.