Question

Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4?

A.)y-3 = 1/16 (x-2)^2
B.)y+3 = -1/16 (x+2)^2
C.)x-2 = 1/16 (y-3)^2

Answer 1

option A.) y-3 = 1/16 (x-2)^2

Explanation:

Answer 2

option A.) y-3 = 1/16 (x-2)^2

Explanation:

we know that

If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola

The equation of a vertical parabola is equal to

`4p(y-k)=(x-h)^(2)`

where

(h,k) is the vertex

In this problem we have

(h,k)=(2,3)

p=4

substitute

`4(4)(y-3)=4(4)(x-2)^(2)`

`16(y-3)=(x-2)^(2)`

`(y-3)=(1/16)(x-2)^(2)`