Question

to solve the system of equations below, grace isolated the variable y in the first equation and then substituted into the second equation. what was the resulting equation? 3y=12x x^2/4+y^2/9=1

Answer 1

`(x^2)/(4)+((4x)^2)/(9)=1`

Explanation:

Given system of equations,

`3y=12x-----(1)`

`(x^2)/(4)+(y^2)/(9)=1----(2)`

As per statement,

Isolating the variable y in the first equation,

`y=(12)/(3)x=4`

Now, substituting into the second equation,

`(x^2)/(4)+((4x)^2)/(9)=1`

Which is the resulting equation,

Simplifying the equation,

`(x^2)/(4)+(16x^2)/(9)=1`

`(9x^2+64x^2)/(36)=1`

`73x^2=36`

Answer 2

The resulting equation is

x^2/4+16x^2/9=1

Explanation:

The given equations are:

3y=12x eq(1)

x^2/4+y^2/9=1 eq(2)

We need to isolate variable y in equation 1

Divide both sides of the equation with 3

3y/3 = 12x/3

y = 4x

Now, substitute the value of y=4x in second equation

x^2/4+y^2/9=1

x^2/4 + (4x)^2/9 = 1

The resulting equation is

x^2/4+16x^2/9=1