Answer:
L = 15cm = 0.15m
A = 0.15 × 0.15 = 0.0225
Sradiation is transfered from bottom
σ = 5.67 × 10⁻⁸ W/m²k
T = 605 c = 878k
Rate of energy transfer
Q = σ × A × E × T⁴
5.67 × 10⁻⁸ × 0.0225 × 2 × 0.8 × 878⁴
1792.17 W
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