Final answer:
The heat energy required to warm 12 grams of water from 98°C to 99°C is calculated using the formula Q = mcΔT. With the specific heat capacity of water and a temperature change of 1°C, the result is 50.16 joules of heat energy needed.
Step-by-step explanation:
The student is asking how to calculate the heat energy required to raise the temperature of 12 grams of water from 98 degrees Celsius to 99 degrees Celsius. To answer this question, you would typically apply the formula Q = mcΔT, where Q is the heat absorbed, m is the mass of the water, c is the specific heat capacity of water (which is approximately 4.18 J/g°C), and ΔT is the change in temperature. Since the temperature change is from 98 to 99 degrees, ΔT is 1 degree Celsius.
The specific heat calculation would look like this:
Q = (12 g) * (4.18 J/g°C) * (1 °C)
Q = (12) * (4.18) * (1)
Q = 50.16 joules
So, 50.16 joules of heat energy is needed to raise the temperature of 12 grams of water by 1 degree Celsius.