Question

Triangle DEF has coordinates D(1,1). E(1,5), and F(5, 1). Triangle DEF is the image of ADEF by a dilation with center (0,0) and a scale factor of 7. What is DF?

D'F =

Answer 1

Answer:Answer:

D'F' = 28

Explanation:

For the vertex D(1, 1)

D'(1 × 7, 1 × 7) = D'(7, 7)

For the vertex E(1, 5)

E'(1 × 7, 5 × 7) = E'(7, 35)

For the vertex F(5, 1)

F'(5 × 7, 1 × 7) = C'(35, 7)

Now to find the D'F':

we do:

y2 - y1 =

and

x2 - x1 =

Here are what the numbers mean

x1 = 7

y1 = 7

x2 = 35

y2 = 7

For the points above (7,7) and (35,7), in which (7,7) is Point 1 and (35,7) is Point 2:

Find the distance along the y-axis.

y2 - y1 = 7 - 7

7 - 7 = 0

Find the distance along the x-axis.

x2 - x1 = 35 - 7

35 - 7 = 28

Now we do: y² and x²

y² = 0² = 0

x² = 28² = 784

Next we add the y and x

0 + 784 = 784

And lastly, we do √x + y

Which is the same as: √0 + 784

√0 + 784 = 28

So the answer is 28

Explanation:

Answer 2

D'F' = 28

Explanation:

For the vertex D(1, 1)

D'(1 × 7, 1 × 7) = D'(7, 7)

For the vertex E(1, 5)

E'(1 × 7, 5 × 7) = E'(7, 35)

For the vertex F(5, 1)

F'(5 × 7, 1 × 7) = C'(35, 7)

Now to find the D'F':

we do:

y2 - y1 =

and

x2 - x1 =

Here are what the numbers mean

x1 = 7

y1 = 7

x2 = 35

y2 = 7

For the points above (7,7) and (35,7), in which (7,7) is Point 1 and (35,7) is Point 2:

Find the distance along the y-axis.

y2 - y1 = 7 - 7

7 - 7 = 0

Find the distance along the x-axis.

x2 - x1 = 35 - 7

35 - 7 = 28

Now we do: y² and x²

y² = 0² = 0

x² = 28² = 784

Next we add the y and x

0 + 784 = 784

And lastly, we do √x + y

Which is the same as: √0 + 784

√0 + 784 = 28

So the answer is 28

pictures of the graph and how to solve