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The function f(x)= -(x+5)(x+1) is down. What is the range of the function?

1 Answer

3 votes

Answer:

(-∞, 4)

Explanation:

"The function f(x)= -(x+5)(x+1) is down" should be "The function f(x)= -(x+5)(x+1) has a parabolic graph that opens down."

Expanding f(x)= -(x+5)(x+1), we get f(x) = -[x^2 + 6x + 5] = -x^2 - 6x - 5.

Here the coefficients are a = -1, b = -6 and c = -5. Thus, the axis of symmetry is

-(-6)

x = ------------ = -3.

2(-1)

The maximum value of the function occurs when x = -3.

We must also find the actual max value.

It is f(-3) = -(-3)^2 - 6(-3) - 5, or 4.

The max value is 4. Thus, the range of this function is (-∞, 4)

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