Question

A disc initially at rest experiences an angular acceleration of 3.11 rad/s for a time of 15.0 s. What will the angular speed of the disc be at this time, in units of rad/s?

Answer 1

The angular speed of the disc be at this time is 46.65 rad/s.

Step-by-step explanation:

Given that,

Angular acceleration
`\alpha= 3.11\ rad/s^2`

Time t =15.0 s

We will calculate the angular speed of the disc

A disc initially at rest.

So,
`\omega=0`

Using rotational kinematics equation

`\omega'=\omega+\alpha\ t`

Where,
`\omega` = initial angular speed

`\omega'` =final angular speed

`\alpha` = angular acceleration

Put the value in the equation

`\omega'=0+3.11*15`

`\omega'=46.65\ rad/s`

Hence, The angular speed of the disc be at this time is 46.65 rad/s.