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What is the value of the discriminant, b2 ? 4ac, for the quadratic equation 0 = x2 ? 4x + 5, and what does it mean about the number of real solutions the equation has?

2 Answers

6 votes

Answer:

b on edge-The discriminant is −4, so the equation has no real solutions.

Explanation:

User Nanette
by
8.4k points
5 votes

Answer:

Discriminant D = -4 , no real solution

Explanation:

Here our equation is


x^(2)-4x+5=0

Discriminant (D)=
b^2-4ac

where

a = coefficient of term containing
x^(2)

b= coefficient of the term containing
x

c is the constant term

hence

a=1 , b =-4 and c=5

Hence


D=b^2-4ac\\D=(-4)^2-4*1*5\\D=16-20\\D=-4\\

Hence D is less than 0 , therefore we do not have any real solution to this quadratic equation.

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