Question

Which equation is represented by the graph below?

Answer 1

Answer: Third option.

Explanation:

Observe that the graph tends to zero when
`x<0` and "y" tends to infinite when
`x>0`

The function
`y=lnx` is not defined for values of "x" less than zero, therefore the equations of the options 1 and 2 do not represent the graph attached.

Observe that the function cuts the y-axis at
`y=1`, while the function
`y=e^x+1` cuts the y-axis at
`y=2`, therefore the equation of the last option does not represent that graph.

Finally, the equation that represents the graph is:

`y=e^x`

Answer 2

For this case we discard options A and B, since by definition, the graph does not correspond to the function of the Neperian logarithm.

We tested option C:

`y = e ^ x`

Doing
`x = 0`we have:

`y = e ^ 0`

Every number raised to zero power is 1.

So, we have:

`y = 1`

We have the point (0,1)

If we try option D:

`y = e ^ x + 1`

Doing x = 0 we have:

`y = e ^ 0 + 1\\y = 1 + 1\\y = 2`

We have the point (0,2)

So, we note that the correct option is option C

ANswer:

Option C