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5 votes
Zahra wants the equation below to have an infinite number of solutions when the missing number is placed in the box.

Zahra wants the equation below to have an infinite number of solutions when the missing-example-1

2 Answers

5 votes

Answer:

c = -3

Explanation:

Call the unknown c

c(x-3) +2x = -(x-5) +4

Distribute the negative sign

c(x-3) +2x = -x+5+4

Combine like terms

c(x-3) +2x = -x +9

Subtract 2x from each side

c(x-3) +2x-2x = -x-2x +9

c(x-3) = -3x+9

Factor a -3 from the right side

c(x-3) = -3(x-3)

Divide by (x-3)

c = -3

The right and left hand side need to be equal for there to be infinite solutions, so c = -3

User Omrakhur
by
8.1k points
4 votes

Answer:

box contains - 3

Explanation:

a(x - 3) + 2x = -(x - 5) +4 Remove the brackets on both sides

ax - 3a + 2x = -x + 5 + 4 Subtract 2x from both sides.

ax - 3a + 2x - 2x = -x - 2x + 9

ax - 3a = - 3x + 9

ax - 3(-3) = - 3x + 9

ax + 9 = - 3x + 9

Now if you make a = -3 then both sides with have - 3 for the x coefficient.

Any number could be put in for x and it will make the answer on both sides equal. Notice you could subtract 9 from both sides and it will not change the condition of the problem.

User Aalex Gabi
by
8.2k points
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