Question

Write the point-slope form of an equation of the line through the points (-2, -3) and (-7, 4).

Answer 1

y+3 = -7/5(x+2)

Explanation:

First we need to find the slope

m = (y2-y1)/(x2-x1)

= (4--3)/(-7--2)

= (4+3)/(-7+2)

=7/-5

= -7/5

The point slope form is y-y1 = m(x-x1)

y--3 = -7/5(x--2)

y+3 = -7/5(x+2)

We could use the second set of points

y-4 = -7/5(x--7)

y-4 =-7/5(x+7)