Answer:
45-2(h-1)<32
Explanation:
This is a problem related to arithmetic progression. The formula we use is that of for nth term

Here


Now we have to analyse a situation when our temperature comes below 32
or
![a_(h)<32[tex]</p><p>[tex]45-2(h-1)<32\\45-2h+2<32\\45-2h<32-2\\45-2h<30\\](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ul2qpy8zpzuc319r0ydd5zyfxo8rjbsh3w.png)
This is our inequality
Solving this

Hence in 8th hours the temperature will be below 32F