Question

Fill in the coefficients that will balance the following reaction:

a0Cr2(SO4)3 + a1AgNO3 -> a2Cr(NO3)3 + a3Ag2SO4

Answer 1

Step-by-step explanation:

can you please put it in boxes so i can find out the answer

Answer 2

a0=1

a1=6

a2=2

a3=3

Step-by-step explanation:

We have to start with the reaction:

`Cr_2(SO_4)_3~+~AgNO_3~->~Cr(NO_3)_3~+~Ag_2SO_4`

We have to start with "
`Cr`". If we want to balance Cr we have to obtain 2 on both sides. Therefore we have to add a "2" on the right side, so:

`Cr_2(SO_4)_3~+~AgNO_3~->~2Cr(NO_3)_3~+~Ag_2SO_4`

Then we can balance "
`NO_3`" as a whole. We have 6 on the right, we have to have the same amount on the left side, so:

`Cr_2(SO_4)_3~+~6AgNO_3~->~2Cr(NO_3)_3~+~Ag_2SO_4`

Then we can balance "
`Ag`". We have 6 on the left, so we have to have the same amount on the right if we already have 2 we have to put a · in front (on the right side) to obtain in total 6, so:

`Cr_2(SO_4)_3~+~6AgNO_3~->~2Cr(NO_3)_3~+~3Ag_2SO_4`

Finally, when we add this last number the
`SO_4` we will have 3 on both sides. Therefore the reaction is already balanced.