For this case we have the following quadratic equation:
![x ^ 2 + 4x-12 = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6oo6zbzhikbtw0fe6ucf8guggrb7v4r8yi.png)
We can factor the equation, for it, we must find two numbers that when multiplied give as result -12 and when summed give as result +4. These numbers are: +6 and -2.
Then, the factorization is given by:
![(x + 6) (x-2) = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4o82y644umbar35asxs6tuv3i30cgcq96u.png)
Thus, the solutions are:
![x_ {1} = - 6\\x_ {2} = 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6olxofc9jv0y0hpysvi1tw2so80tkzuua3.png)
Answer:
![x_ {1} = - 6\\x_ {2} = 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6olxofc9jv0y0hpysvi1tw2so80tkzuua3.png)