Hello!
The correct option is:
C.

Why?
To find which of the given options are not the result of a substitution in the given system, we need to isolate the variable in function of the other variable, and then substitute it.
So, substituting and discarding, we have:
- First equation:

Isolating "y", we have:

Then, substituting it into the second equation, we have:


We have that it's a result of a substitutiong in the following system (option A)
- Second equation:

Isolating "y", we have:

Then, substituting it into the first equation, we have:

.
So, the correct option is:
C. [tex]2(y+1)+y=7" src="
![image]()
Have a nice day!