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The electric field between square plates of a parallel-plate capacitor has magnitude E. The potential across the plates is maintained with constant voltage by a battery as they are pulled apart to twice their original separation, which is small compared to the dimensions of the plates. The magnitude of the electric field between the plates is now equal to a)E b)E/4 c)E/2 d)4E e)2E

User Dikla
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1 Answer

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Answer:

the Answer is c: E/2

Step-by-step explanation:

see attachment

The electric field between square plates of a parallel-plate capacitor has magnitude-example-1
User Emanuele Bezzi
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