Answer:
Events D and C are mutually exclusive.
Explanation:
Two events D and C are mutually exclusive if
![Pr(D\cup C)=Pr(D)+Pr(C)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aetg5fwbx5xqd3i1oloncd7nuxohzvzd47.png)
Find these probabilities. In a standard deck of 52 playing cards there are 13 diamond cards and 13 club cards.
The probabilty of chosing diamond is
![Pr(D)=(13)/(52)=(1)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/61gv0a61x2fxgvrso7c5ti77hh8oyzmjxc.png)
The probabilty of chosing club is
![Pr(C)=(13)/(52)=(1)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n631eh3dcf522g68j1ttxjfo6yb0bxas5e.png)
The probabilty of chosing diamond or club is
![Pr(D\cup C)=(13+13)/(52)=(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t0c1ouvowko23mfysua6blgdakn7ceyuo0.png)
Since
![(1)/(2)=(1)/(4)+(1)/(4),](https://img.qammunity.org/2020/formulas/mathematics/middle-school/61ly4eajzc95d2ycy5h440908l9y8wjupq.png)
events D and C are mutually exclusive.