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A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds: f(t) = −16t2 + 48t + 100 The average rate of change of f(t) from t = 3 seconds to t = 5 seconds is _____feet per second.

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Answer:

The average rate of change of f(t) from t = 3 seconds to t = 5 seconds is __-80___feet per second.

Explanation:

The average change rate m is calculated using the following formula


m=(f(t_2)-f(t_1))/(t_2-t_1)

In this case
f(t) = -16t^2 + 48t + 100,
t_2 = 5\ s\ \ , t_1=3\ s

Then


f(t_2) = f(5) =-16(5)^2 + 48(5) + 100


f(t_2) = -60


f(t_1) = f(3) =-16(3)^2 + 48(3) + 100


f(t_1) = 100

Finally


m=((-60)-100)/(5-3)


m=-80

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