Δλ = 3.103 m.
To solve this problem we have to know the speed of sound in both elements water and ice.
Element Speed of sound
Water (25°C) 1493 m/s
Ice 3200 m/s
The velocity of a wave is given by the equation v = λf, where λ is the wavelength, and f is the frecuency of the wave.
In order to calculate the wavelength we have to clear λ in the equation v = λf, resulting:
λ = v/f
Calculating the wavelength in both elements:
λ(water) = 1493 m/s / 550 Hz = 2.715 m
λ(ice) = 3200 m/s / 550 Hz = 5.818 m
So, the difference in wavelength between the wave produced in ice and the wave produced in water is:
Δλ = λ(water) - λ(ice) = 5.818 m - 2.715 m
Δλ = 3.103 m