Answer:
The width can be 5 ft or the width can be 4 ft
Explanation:
Perimeter = 2 (l+w) for a rectangle
Area = l*w for a rectangle
Using perimeter
18 = 2(l+w)
Divide by 2
18/2 = 2/2 (l+w)
9 = l+w
Solving for l
9-w = l
Using area
20 = l*w
Substituing for l
20 = (9-w) * w
20 = 9w - w^2
Subtract 20 from each side
20-20 =-w^2 +9w -20
0 = -w^2 +9w -20
Multiply by -1
0 = w^2 -9w+20
Factor
0 = (w-5) (w-4)
Using the zero product property
w-5 = 0 w-4 = 0
w= 5 w=4
The width can be 5 ft or the width can be 4 ft