Answer:
Explanation:
What is the VALUE OF 3r=10+5 when r=10?
substitute 10 for r in 3r=10+5. We get:
3(10) = 10 + 5, or 30 = 15. This equation is FALSE when r = 10.
You could solve the equation for r, however:
3r=10+5 becomes 3r = 15, and so r = 5. 5 is a solution; 10 is not a solution.