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a shot putter releases the shot some distance above the level ground with a velocity of 12.0 m/s, 51.0 ∘above the horizontal. the shot hits the ground 2.08 s later. you can ignore air resistance. how far did she throw the shot?

User Tomvo
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1 Answer

4 votes

Answer:

15.7 m

Step-by-step explanation:

The range (horizontal distance) of the projectile is determined only by its horizontal motion.

The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:


v_x = v cos \theta

where

v = 12.0 m/s is the initial velocity


\theta=51.0^(\circ) is the angle between the direction of v and the horizontal

Substituting,


v_x = (12.0 m/s)(cos 51.0^(\circ) )=7.55 m/s

We know that the projectile hits the ground in a time of

t = 2.08 s

so the horizontal distance covered is


d = v_x t = (7.55 m/s)(2.08 s)=15.7 m

User SNeumann
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