For this case we must find the inverse of the following function:
![g (x) = 2x + 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m7gkr4m684nedv6o39dq53ngxkm8a48o4j.png)
Replace g(x) with y:
![y = 2x + 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jadn2hzibd1wpl7ewdnl984n9iouea4b2j.png)
We exchange the variables:
![x = 2y + 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9sz4cx44g402639j9aavsto2sqi5wyawnm.png)
We solve for "y":
We subtract 4 on both sides of the equation:
![x-4 = 2y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a1p9td1rihd1hm4x0m82a3mgnhi3mz68j2.png)
We divide between 2 on both sides of the equation:
![y = \frac {x} {2} -2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lzskujfls5r3tcehr2uj1071heekuh4tph.png)
We change y by
:
![g ^ {- 1} (x) = \frac {x} {2} -2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hrgfmrx627ulbkk8f54t12xfq2cjzdqs3w.png)
Answer:
![g ^ {- 1} (x) = \frac {x} {2} -2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hrgfmrx627ulbkk8f54t12xfq2cjzdqs3w.png)